document.write( "Question 990036: Sara left downtown Portland, and 3 hours later, sam left going 43mph faster to catch up. After another 2 hours, Sam caught up. Find saras average speed? \n" ); document.write( "
Algebra.Com's Answer #610149 by Edwin McCravy(20056)\"\" \"About 
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document.write( "Let her average speed by r mph.\r\n" );
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document.write( "After 3 hours, since d=rt, she was r∙3 or 3r miles down the road \r\n" );
document.write( "when Sam left.\r\n" );
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document.write( "So the distance between them when Sam left was 3r.\r\n" );
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document.write( "His catch-up rate was 43 mph to catch up the 3r distance between them,\r\n" );
document.write( "so since d=rt, 3r = 43∙2\r\n" );
document.write( "               3r = 86\r\n" );
document.write( "                r = 86/3 = 28 2/3 mph\r\n" );
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document.write( "Edwin
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