document.write( "Question 990001: if sin A=1/3 then tan A will be: \n" ); document.write( "

Algebra.Com's Answer #610148 by Alan3354(69443) $\"\"$ $\"About$

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if sin A=1/3 then tan A will be:
\n" ); document.write( "==============
\n" ); document.write( "sin = y/r = 1/3
\n" ); document.write( "y = 1, r = 3
\n" ); document.write( "---
\n" ); document.write( " $\"x+=+sqrt%28r%5E2+-+y%5E2%29+=+sqrt%289-1%29+=+2sqrt%282%29\"$
\n" ); document.write( "tan = y/x
\n" ); document.write( "tan(A) = sqrt(2)/4
\n" ); document.write( "=============================
\n" ); document.write( "Or,
\n" ); document.write( " $\"cos%28A%29+=+sqrt%281+-+sin%5E2%28A%29%29+=+sqrt%288%29%2F3\"$
\n" ); document.write( "tan = sin/cos = 1/sqrt(8)
\n" ); document.write( "tan = sqrt(2)/4\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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