document.write( "Question 990006: The second of three numbers is one less than the first. The third number is five less than twice the second. If the third number exceeds the first number by 12, find the three numbers \n" ); document.write( "
Algebra.Com's Answer #610147 by ankor@dixie-net.com(22740)\"\" \"About 
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let the three number be a, b, c
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\n" ); document.write( "write an equation for each statement
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\n" ); document.write( "The second of three numbers is one less than the first.
\n" ); document.write( "b = a - 1
\n" ); document.write( " The third number is five less than twice the second.
\n" ); document.write( "c = 2b - 5
\n" ); document.write( " If the third number exceeds the first number by 12,
\n" ); document.write( "c = a + 12
\n" ); document.write( ":
\n" ); document.write( "find the three numbers
\n" ); document.write( "In the 2nd equation, replace c with (a+12)
\n" ); document.write( "a + 12 = 2b - 5
\n" ); document.write( "a - b = -5 - 12
\n" ); document.write( "a - 2b = -17
\n" ); document.write( "replace b with (a-1)
\n" ); document.write( "a - 2(a-1) = -17
\n" ); document.write( "a - 2a + 2 = -17
\n" ); document.write( "a - 2a = -17 - 2
\n" ); document.write( "-a = -19
\n" ); document.write( "a = 19
\n" ); document.write( "find
\n" ); document.write( "b = 19 - 1
\n" ); document.write( "b = 18
\n" ); document.write( "find c
\n" ); document.write( "c = 19 + 12
\n" ); document.write( "c = 31
\n" ); document.write( ":
\n" ); document.write( "The three number: 19, 18, 31 \n" ); document.write( "
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