document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=989888>Question 989888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 21 is added to a number, the result is 38 less than twice the number. Find the number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610123 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "We will use \"x\" to represent a number.\r<BR>\n" );
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document.write( "If 21 is added to a number --> (x + 21)\r<BR>\n" );
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document.write( "the result is 38 less than twice the number --> (= 2x - 38)\r<BR>\n" );
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document.write( "The equation:\r<BR>\n" );
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document.write( "x + 21 = 2x - 38\r<BR>\n" );
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document.write( "Solve,\r<BR>\n" );
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document.write( "x - 2x = -21 - 38\r<BR>\n" );
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document.write( "-x = -59 (divide both sides by -1)\r<BR>\n" );
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document.write( "x = 59 is the final answer.\r<BR>\n" );
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document.write( "If you plug x = 59 back into the equation both sides will be equal.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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