document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=989927>Question 989927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jake is 5 years older than john. jill is twice as old as john. jan is 5 years younger than john. the sum of all the ages is equal to 75. find their ages.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610092 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "J=john's age; A=Jake's age=J+5; I=Jill's age=2J; <BR>\n" );
document.write( "N=Jan's age=J-5<BR>\n" );
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document.write( "J+A+I+N=75<BR>\n" );
document.write( "J+(J+5)+(2J)+(J-5)=75<BR>\n" );
document.write( "5J=75<BR>\n" );
document.write( "J=15<BR>\n" );
document.write( "ANSWER 1: John is 15 years old.<BR>\n" );
document.write( "A=J+5=15+5=20<BR>\n" );
document.write( "ANSWER 2: Jake is 20 years old.<BR>\n" );
document.write( "I=2J=2(15)=30<BR>\n" );
document.write( "ANSWER 3: Jill is 30 years old.<BR>\n" );
document.write( "N=J-5=15-5=10<BR>\n" );
document.write( "ANSWER 4: Jan is 10 years old.\r<BR>\n" );
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