document.write( "Question 989908: how many gal. of a 90% sugar solution must be mixed with 3 gal. of a 60% sugar solution to make a 81% solution \n" ); document.write( "
Algebra.Com's Answer #610089 by macston(5194)\"\" \"About 
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\n" ); document.write( "N=amount of 90% solution.
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\n" ); document.write( "0.60(3 gal)+0.90(N)=0.81(N+3)
\n" ); document.write( "1.8gal+0.90N=0.81N+2.43gal
\n" ); document.write( "0.09N=0.63gal
\n" ); document.write( "N=7gal
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\n" ); document.write( "ANSWER You should mix 7 gallons of 90% solution with 3 gallons
\n" ); document.write( "of 60% solution to get 10 gallons of 81% solution.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.60(3gal)+0.90(7gal)=0.81(10gal)
\n" ); document.write( "1.8gal+6.3gal=8.1gal
\n" ); document.write( "8.1gal=8.1gal
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