document.write( "Question 989901: find a number that;
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document.write( "The last digit is even
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document.write( "Sum of the digits is divisible by 3
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document.write( "The last 2 digits are divisible by 4
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document.write( "The last digit is 0 or 5
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document.write( "The number is divisible by 2 and 3
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document.write( "The last 3 digits form a number divisible by 8
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document.write( "The sum of the digits is divisible by 9
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document.write( "The last digit is 0 \n" );
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Algebra.Com's Answer #610080 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website!
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In short, we know this number has the following factors: 2,3,4,5,6,8,9,10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There could be other factors or repeats of those factors above. Let's say that there is only one copy of each and only those factors are there\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply out all the factors: 2*3*4*5*6*8*9*10 = 518,400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the smallest number possible is 518,400 Any other multiple of this number works as well. \n" ); document.write( " |