document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=989770>Question 989770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a problem of  putting the following into an linear equation. A company invested $42000 into two simple interest accounts. The annual interest rate on one of the accounts is 4.5% while the rate on the other is 6%. How much should the company invest in each account so that the two accounts will produce an equal annual interest account? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610037 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The annual interest earned on each account is I = P*r, where P = the principal and r = the interest rate<BR>\n" );
document.write( "Let P1 and P2 be the amounts invested in each account<BR>\n" );
document.write( "The total amount, P = P1 + P2<BR>\n" );
document.write( "The interest earned on account 1 will be P1*r1 = 0.045*P1<BR>\n" );
document.write( "The interest earned on account 2 will be P2*r2 = 0.06(P-P1)<BR>\n" );
document.write( "Setting the two amounts equal to each other, and putting in all the numbers, we have<BR>\n" );
document.write( "0.045P1 = 0.06(42000-P1)<BR>\n" );
document.write( "Solving for P1 gives P1 = 24000<BR>\n" );
document.write( "Therefore P2 = 18000<BR>\n" );
document.write( "Ans: 24000, 18000 </SPAN>\n" );
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