document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=989644>Question 989644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: BC=DE<BR>\n" );
document.write( "Prove:AB+DE=AC </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610008 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "If BC = DE (given) then by the segment addition postulate AB + BC = AC. Therefore, it follows that AB + DE = AC by substitution. <BR>\n" );
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document.write( "*Essentially you are replacing BC with DE in the postulate.\r<BR>\n" );
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