document.write( "Question 989699: If C(n,3)=C(n,4),then the value of n?????please help me to solve this problem. \n" ); document.write( "
Algebra.Com's Answer #609934 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "C(n,3)=n!/(3!(n-3)!) \n" ); document.write( ". \n" ); document.write( "C(n,4)=n!/(4!(n-4)!) \n" ); document.write( ". \n" ); document.write( "n!/(3!(n-3)!)=n!/(4!(n-4)!) Divide each side by n! \n" ); document.write( "1/(3!(n-3)!)=1/(4!(n-4)!) Cross multiply \n" ); document.write( "3!(n-3)!=4!(n-4)! Divide each side by 3! \n" ); document.write( "(n-3)!=4(n-4)! Divide each side by (n-4)!*(Note below) \n" ); document.write( "n-3=4(1) \n" ); document.write( "n-3=4 \n" ); document.write( "n=7 \n" ); document.write( "ANSWER: n=7 \n" ); document.write( ". \n" ); document.write( "*NOTE: (n-3)!=(n-3)(n-4)! so (n-3)!/(n-4)!=(n-3) \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "n!/(3!(n-3)!)=n!/(4!(n-4)!)= \n" ); document.write( "7!/(3!(7-3!))=7!/(4!(7-4)!)= \n" ); document.write( "7!/(3!4!)=7!/(4!3!) \n" ); document.write( "(7*6*5)/(3*2*1)=(7*6*5)/(3*2*1) \n" ); document.write( "210/6=210/6 \n" ); document.write( "35=35\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |