document.write( "Question 989668: I have pennies, nickels, and dimes. If 2 times the amount of quarters is dimes, and there's 2 nickles more than there are quarters. The total amount is $7.60. how many of each coin do i have? explain your answer. \n" ); document.write( "
Algebra.Com's Answer #609925 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
I went through a solution process earlier, but then thought more about the description, and decided not to try to finish.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You \"have\" pennies, nickels and dimes;
\n" ); document.write( "and then you have a description involving quarters.
\n" ); document.write( "What is the exact problem description, word-for-word?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "NO PENNIES; QUARTERS INSTEAD.
\n" ); document.write( "q, d, n, quarters nickels dimes
\n" ); document.write( "\"system%28d=2q%2Cn=q%2B2%2C0.25q%2B0.1d%2B0.05n=7.60%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply the money equation by \"20\".
\n" ); document.write( "\"5q%2B2d%2Bn=152\"
\n" ); document.write( "Substitute the other relationships described.
\n" ); document.write( "\"5q%2B2%282q%29%2B%28q%2B2%29=152\"
\n" ); document.write( "Solve for q first ; and then go back to the other two relationships to evaluate d and n.
\n" ); document.write( "
\n" );