document.write( "Question 989679: How 1/i becomes i/(-1)? \n" ); document.write( "
Algebra.Com's Answer #609911 by jim_thompson5910(35256)\"\" \"About 
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\"1%2Fi\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2Ai%29%2F%28i%2Ai%29\" Multiply top and bottom by i\r
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\n" ); document.write( "\n" ); document.write( "\"i%2F%28i%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"i%2F%28-1%29\" Use the idea that \"i%5E2=-1\"\r
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\n" ); document.write( "\n" ); document.write( "So \"1%2Fi\" is equivalent to \"i%2F%28-1%29\"
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