document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=989673>Question 989673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A gardener is planting flowers in a circular bed. If he plants 1256 flowers which are p.lanted 4 to a square metre,find the diameter of this bed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609907 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"he plants 1256 flowers which are planted 4 to a square metre\", so 1256/4 = 314 square meters are used up.\r<BR>\n" );
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document.write( "Area of a circle<BR>\n" );
document.write( "A = pi*r^2\r<BR>\n" );
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document.write( "Plug in the area A = 314 and solve for r\r<BR>\n" );
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document.write( "A = pi*r^2<BR>\n" );
document.write( "314 = pi*r^2 ... replace A with 314<BR>\n" );
document.write( "314 = 3.14*r^2 ... replace pi with 3.14<BR>\n" );
document.write( "314/3.14 = (3.14*r^2)/3.14 ... Divide both sides by 3.14.<BR>\n" );
document.write( "100 = r^2<BR>\n" );
document.write( "r^2 = 100<BR>\n" );
document.write( "sqrt(r^2) = sqrt(100) ... take the square root of both sides<BR>\n" );
document.write( "r = 10 \r<BR>\n" );
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document.write( "So the radius is 10, making the diameter 2*10 = <font color=\"red\">20 meters</font> </SPAN>\n" );
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