document.write( "Question 989648: x-y+2z=-7
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document.write( "y+z=1
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document.write( "x=2y+3z\r
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document.write( "I did start this problem but got stuck fairly quickly. We're supposed to be solving using substitution or elimination. Please get back to me as soon as possible, thanks! \n" );
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Algebra.Com's Answer #609901 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! x-y+2z=-7 \n" ); document.write( "y+z=1 \n" ); document.write( "x=2y+3z \n" ); document.write( "============== \n" ); document.write( "Sub for x in the 1st eqn. \n" ); document.write( "(2y + 3z) - y + 2z = 7 \n" ); document.write( "y + 4z = 7 \n" ); document.write( "y + z = 1 \n" ); document.write( "=================== Subtract \n" ); document.write( "3z = 6 \n" ); document.write( "z = 2 ******************* \n" ); document.write( "------ \n" ); document.write( "y + z = 1 \n" ); document.write( "y = -1 ********************** \n" ); document.write( "------ \n" ); document.write( "Sub for y & z anywhere to find x. \n" ); document.write( " \n" ); document.write( " |