document.write( "Question 989648: x-y+2z=-7
\n" ); document.write( "y+z=1
\n" ); document.write( "x=2y+3z\r
\n" ); document.write( "\n" ); document.write( "I did start this problem but got stuck fairly quickly. We're supposed to be solving using substitution or elimination. Please get back to me as soon as possible, thanks!
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Algebra.Com's Answer #609901 by Alan3354(69443)\"\" \"About 
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x-y+2z=-7
\n" ); document.write( "y+z=1
\n" ); document.write( "x=2y+3z
\n" ); document.write( "==============
\n" ); document.write( "Sub for x in the 1st eqn.
\n" ); document.write( "(2y + 3z) - y + 2z = 7
\n" ); document.write( "y + 4z = 7
\n" ); document.write( "y + z = 1
\n" ); document.write( "=================== Subtract
\n" ); document.write( "3z = 6
\n" ); document.write( "z = 2 *******************
\n" ); document.write( "------
\n" ); document.write( "y + z = 1
\n" ); document.write( "y = -1 **********************
\n" ); document.write( "------
\n" ); document.write( "Sub for y & z anywhere to find x.
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