document.write( "Question 84669: PLEASE PLEASE. I'M IN DESPERATE NEED OF HELP!\r
\n" ); document.write( "\n" ); document.write( "A mosquito population is growing at a rate of 8% each day and the current population is estimated at 200,000. Use y=y sub 0 times e^0.08t as the equation for the mosquito population.\r
\n" ); document.write( "\n" ); document.write( "a) how many mosquitoes are there expected to be in 10 days?\r
\n" ); document.write( "\n" ); document.write( "b) how many days will it take for the mosquito population to reach one million?
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Algebra.Com's Answer #60986 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"y+=+y%5Bo%5D%2Ae%5E%280.08%2At%29\"
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\n" ); document.write( "At time t = 0, the mosquito population represented in this equation by y is 200,000.
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\n" ); document.write( "t represents the number of days since day zero when t = 0
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\n" ); document.write( "Note that on day zero (when t = 0) the part of the equation represented by:
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\n" ); document.write( "\"e%5E%280.08%2At%29\"
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\n" ); document.write( "becomes
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\n" ); document.write( "\"e%5E%280.08%2A0%29+=+e%5E0+=+1\" because any number to the 0 power is 1 by definition.
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\n" ); document.write( "Since this is 1 the equation is reduced to \"y+=+y%5Bo%5D\" and since the mosquito population
\n" ); document.write( "is known to be 200,000 at this time, we know that \"200000+=+y%5Bo%5D\". So we can substitute
\n" ); document.write( "200,000 for \"y%5Bo%5D\" and the equation becomes:
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\n" ); document.write( "\"y+=+%28200000%29%2Ae%5E%280.08%2At%29\"
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\n" ); document.write( "Now to the problem. In ten days (when t = 10) the population of mosquitoes becomes:
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\n" ); document.write( "\"y+=+%28200000%29%2Ae%5E%280.08%2A10%29+=+%28200000%29%2Ae%5E%280.8%29\"
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\n" ); document.write( "Calculator time. \"e%5E0.8+=+2.225540928\". Substitute this into the equation and it becomes:
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\n" ); document.write( "\"y+=+%28200000%29%2A%282.225540928%29=445108.1857\"
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\n" ); document.write( "Rounding to the nearest whole number, the equation tells us that in 10 days there will
\n" ); document.write( "be 445108 mosquitoes.\r
\n" ); document.write( "\n" ); document.write( "To find out how many days it will take for the mosquito population to reach a million, set
\n" ); document.write( "y equal to 1,000,000 in the equation and solve for t. The equation becomes:
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\n" ); document.write( "\"1000000+=+200000%2Ae%5E%280.08%2At%29\"
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\n" ); document.write( "Simplify by dividing both sides by 200,000 to get:
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\n" ); document.write( "\"5+=+e%5E%280.08%2At%29\"
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\n" ); document.write( "Take the natural log of both sides and you get:
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\n" ); document.write( "\"ln%285%29+=+ln%28e%5E%280.08%2At%29%29\"
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\n" ); document.write( "The ln of 5 is (by calculator) 1.609437912. Substitute this:
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\n" ); document.write( "\"1.609437912+=+ln%28e%5E%280.08%2At%29%29\"
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\n" ); document.write( "And by the power rule of logarithms, in the log of a quantity that is raised to an exponent,
\n" ); document.write( "you can bring the exponent out and make it the multiplier of the log of the quantity that
\n" ); document.write( "remains. In this case that means \"ln%28e%5E%280.08%2At%29%29+=+0.08%2At%2Aln%28e%29\". Substitute the right
\n" ); document.write( "side into the equation in place of \"ln%28e%5E%280.08%2At%29%29\" and the result is:
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\n" ); document.write( "\"1.609437912+=+0.08%2At%2Aln%28e%29%29\"
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\n" ); document.write( "But ln(e) = 1. Substitute this and the equation reduces to:
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\n" ); document.write( "\"1.609437912+=+0.08%2At%29\"
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\n" ); document.write( "Solve for t by dividing both sides of this equation by 0.08 and the answer becomes:
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\n" ); document.write( "\"t+=+1.609437912%2F0.08+=+20.11797391\"
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\n" ); document.write( "So it will take a little more than 20 days for the colony of mosquitoes to be more than
\n" ); document.write( "one million in population. The population should slightly exceed a million in 20 days and
\n" ); document.write( "3 hours.
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\n" ); document.write( "Hope this helps you to understand the problem.
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