document.write( "Question 84669: PLEASE PLEASE. I'M IN DESPERATE NEED OF HELP!\r
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document.write( "A mosquito population is growing at a rate of 8% each day and the current population is estimated at 200,000. Use y=y sub 0 times e^0.08t as the equation for the mosquito population.\r
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document.write( "a) how many mosquitoes are there expected to be in 10 days?\r
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document.write( "b) how many days will it take for the mosquito population to reach one million?
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Algebra.Com's Answer #60986 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "At time t = 0, the mosquito population represented in this equation by y is 200,000. \n" ); document.write( ". \n" ); document.write( "t represents the number of days since day zero when t = 0 \n" ); document.write( ". \n" ); document.write( "Note that on day zero (when t = 0) the part of the equation represented by: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "becomes \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Since this is 1 the equation is reduced to \n" ); document.write( "is known to be 200,000 at this time, we know that \n" ); document.write( "200,000 for \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now to the problem. In ten days (when t = 10) the population of mosquitoes becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Calculator time. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Rounding to the nearest whole number, the equation tells us that in 10 days there will \n" ); document.write( "be 445108 mosquitoes.\r \n" ); document.write( "\n" ); document.write( "To find out how many days it will take for the mosquito population to reach a million, set \n" ); document.write( "y equal to 1,000,000 in the equation and solve for t. The equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Simplify by dividing both sides by 200,000 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Take the natural log of both sides and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The ln of 5 is (by calculator) 1.609437912. Substitute this: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And by the power rule of logarithms, in the log of a quantity that is raised to an exponent, \n" ); document.write( "you can bring the exponent out and make it the multiplier of the log of the quantity that \n" ); document.write( "remains. In this case that means \n" ); document.write( "side into the equation in place of \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "But ln(e) = 1. Substitute this and the equation reduces to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve for t by dividing both sides of this equation by 0.08 and the answer becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So it will take a little more than 20 days for the colony of mosquitoes to be more than \n" ); document.write( "one million in population. The population should slightly exceed a million in 20 days and \n" ); document.write( "3 hours. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem. \n" ); document.write( " |