document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84668>Question 84668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP ME PLEASE!<BR>\n" );
document.write( "log base 8 (x+2) - log base 8 (x) = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60985 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All logarithms are to the base 8 in this problem.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%288%2C%28x%2B2%29%29+-+log%288%2Cx%29+=+1 ALIGN=MIDDLE  ALT=\"log%288%2C%28x%2B2%29%29+-+log%288%2Cx%29+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "when two logs are subtracted, it is equivalent to the log of their quotient in which the<BR>\n" );
document.write( "negative log becomes the denominator.  By this rule the problem can be converted to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%288%2C%28%28x%2B2%29%2Fx%29%29+=+1 ALIGN=MIDDLE  ALT=\"log%288%2C%28%28x%2B2%29%2Fx%29%29+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now you can convert this to exponential form by raising the base (8) to the exponent<BR>\n" );
document.write( "on the right side of the equation (1) and setting that equal to the term on which the log<BR>\n" );
document.write( "function is operating <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28x%2B2%29%2Fx%29 ALIGN=MIDDLE  ALT=\"%28%28x%2B2%29%2Fx%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. In equation form this is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%5E1+=+%28x%2B2%29%2Fx+ ALIGN=MIDDLE  ALT=\"8%5E1+=+%28x%2B2%29%2Fx+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "This simplifies to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8+=+%28x%2B2%29%2Fx ALIGN=MIDDLE  ALT=\"8+=+%28x%2B2%29%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Get rid of the denominator on the right side by multiplying both sides by x to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2Ax+=+%28x%29%2A%28x%2B2%29%2Fx+=%28cross%28x%29%29%2A+%28x%2B2%29%2F%28cross%28x%29%29=+x%2B2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So the equation has been reduced to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x+=+x%2B2 ALIGN=MIDDLE  ALT=\"8x+=+x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Subtract x from both sides of this equation to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7x+=+2 ALIGN=MIDDLE  ALT=\"7x+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Finally, divide both sides of the equation to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2%2F7 ALIGN=MIDDLE  ALT=\"x+=+2%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "That's the answer to the problem. Hope this helps you to understand a little bit more about<BR>\n" );
document.write( "methods you can use to solve logarithmic equations.  The conversion from logarithmic<BR>\n" );
document.write( "form to exponential form is especially useful and you should become familiar with it. </SPAN>\n" );
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