document.write( "Question 989348: A building in a city has a rectangular base. The length of the base measures
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Algebra.Com's Answer #609702 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "A building in a city has a \"rectangular\" base. \r
\n" ); document.write( "\n" ); document.write( "if the length \"L\" of the base measures \"70ft\" less than three times the width \"W\", we have \r
\n" ); document.write( "\n" ); document.write( " \"L=3W-70ft\"\r
\n" ); document.write( "\n" ); document.write( "if the perimeter \"P=2%28L%2BW%29\" of the base is \"900ft\", than\r
\n" ); document.write( "\n" ); document.write( "\"2%28L%2BW%29=900ft\".....substitute \"3W-70ft\" for \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"2%283W-70ft%2BW%29=900ft\"...........solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"2%284W-70ft%29=900ft\"\r
\n" ); document.write( "\n" ); document.write( "\"8W-140ft=900ft\"\r
\n" ); document.write( "\n" ); document.write( "\"8W=900ft%2B140ft\"\r
\n" ); document.write( "\n" ); document.write( "\"8W=1040ft\"\r
\n" ); document.write( "\n" ); document.write( "\"W=1040ft%2F8\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28W=130ft%29\"\r
\n" ); document.write( "\n" ); document.write( "now find \"L\":\r
\n" ); document.write( "\n" ); document.write( " \"L=3W-70ft\"\r
\n" ); document.write( "\n" ); document.write( " \"L=3%2A130ft-70ft\"\r
\n" ); document.write( "\n" ); document.write( " \"L=390ft-70ft\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28L=320ft%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, the dimensions of the base are:\"highlight%28L=320ft%29\", \"highlight%28W=130ft%29\"\r
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