document.write( "Question 989333: A body subject to air resistance is allowed to fall from the top of a 36 m tower. Given that the distance s metres, through which it falls in t seconds, is given by
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document.write( "s = 5 t^2 − t^3 / 3, 0 ≤ t ≤ 3\r
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document.write( "what is the acceleration after 3 seconds, in m/s2. Please give an exact, possibly fractional, answer (no decimals).\r
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document.write( "Do I differentiate twice?
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document.write( "So, (10t - 2t^2) / 3
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document.write( "Then (10 - 4t) / 3\r
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document.write( "I'm stuck!\r
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document.write( "THANK YOU \n" );
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Algebra.Com's Answer #609677 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A body subject to air resistance is allowed to fall from the top of a 36 m tower. Given that the distance s metres, through which it falls in t seconds, is given by \n" ); document.write( "s = 5 t^2 - t^3 / 3, 0 < t < 3\r \n" ); document.write( "\n" ); document.write( "what is the acceleration after 3 seconds, in m/s2. Please give an exact, possibly fractional, answer (no decimals).\r \n" ); document.write( "\n" ); document.write( "Do I differentiate twice? \n" ); document.write( "--------------- \n" ); document.write( "Acceleration is the 2nd derivative of displacement. \n" ); document.write( "--- \n" ); document.write( "So, (10t - 2t^2) / 3 ***** = (10t - 3t^2)/3 \n" ); document.write( "Then (10 - 4t) / 3 ***** = (10 - 6t)/3 \n" ); document.write( "At t = 3: s\" = (10 - 18)/3 = -8/3 \n" ); document.write( "------------ \n" ); document.write( "Seems odd that the acceleration is negative. \n" ); document.write( "-- \n" ); document.write( "Maybe it's: \n" ); document.write( "s = 5t^2 - t^3/3 \n" ); document.write( "s' = 10t - t^2 \n" ); document.write( "s\" = 10 - 2t \n" ); document.write( "s\"(3) = 4 m/sec/sec \n" ); document.write( "================ \n" ); document.write( "I have doubts about the given equation. \n" ); document.write( " \n" ); document.write( " |