document.write( "Question 989269: One number is 8 more than another number. The sum of their reciprocals is 1/3. Find the two numbers. \n" ); document.write( "

Algebra.Com's Answer #609662 by themasterofcircuits(27) $\"\"$ $\"About$

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(1) y=x+8
\n" ); document.write( "(2) 1/x+1/y=1/3\r
\n" ); document.write( "\n" ); document.write( "Sub (1) into (2)\r
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\n" ); document.write( "\n" ); document.write( "(1/x)+(1/(x+8))=1/3\r
\n" ); document.write( "\n" ); document.write( "(x+8)/(x(x+8))+(x)/(x(x+8))=1/3\r
\n" ); document.write( "\n" ); document.write( "(x+8)/(x^2+8x)+(x)/(x^2+8x)=1/3\r
\n" ); document.write( "\n" ); document.write( "2x+8/(x^2+8x)=1/3\r
\n" ); document.write( "\n" ); document.write( "2x+8=1/3(x^2+8x)\r
\n" ); document.write( "\n" ); document.write( "1/3x^2+8/3x-2x-8=0\r
\n" ); document.write( "\n" ); document.write( "1/3x^2+2/3x-8=0\r
\n" ); document.write( "\n" ); document.write( "x^2+2x-24=0
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\n" ); document.write( "[x=4, x=-6]\r
\n" ); document.write( "\n" ); document.write( "If x=4:\r
\n" ); document.write( "\n" ); document.write( "y=x+8\r
\n" ); document.write( "\n" ); document.write( "[y=12]\r
\n" ); document.write( "\n" ); document.write( "If x=-6\r
\n" ); document.write( "\n" ); document.write( "y=x+8\r
\n" ); document.write( "\n" ); document.write( "y=[2]\r
\n" ); document.write( "\n" ); document.write( "-Aμstin\r
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