document.write( "Question 989149: ABC is an equilateral triangle in which BC=2cm. Find the perpendicular distance from A to BC. \n" ); document.write( "

Algebra.Com's Answer #609618 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "The perpendicular forms a right triangle with hypotenuse AB=2cm,
\n" ); document.write( "one leg is 1/2(BC)=1cm.
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\n" ); document.write( "Let c=AB=2cm, b=1/2(BC)=1cm, a=perpendicular distance from A to BC
\n" ); document.write( ".
\n" ); document.write( " $\"a%5E2%2Bb%5E2=c%5E2\"$
\n" ); document.write( " $\"a%5E2=c%5E2-b%5E2\"$
\n" ); document.write( " $\"a=sqrt%28c%5E2-b%5E2%29\"$
\n" ); document.write( " $\"a=sqrt%28%282cm%29%5E2-%281cm%29%5E2%29\"$
\n" ); document.write( " $\"a=sqrt%284cm%5E2-1cm%5E2%29\"$
\n" ); document.write( " $\"a=sqrt%283cm%5E2%29\"$
\n" ); document.write( " $\"a=sqrt%283%29cm\"$
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\n" ); document.write( "ANSWER: The perpendicular distance is $\"sqrt%283%29cm\"$ .
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