document.write( "Question 989005: Joy can do a job in 7 hours, while it takes Lucy only 5 hours to do same job. How long will it take them to do the same job if they work together?
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Algebra.Com's Answer #609523 by ankor@dixie-net.com(22740)\"\" \"About 
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Joy can do a job in 7 hours, while it takes Lucy only 5 hours to do same job.
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\n" ); document.write( "let t = time required when working together
\n" ); document.write( "let the completed job = 1
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\n" ); document.write( "A shared work equation, each will do a fraction of the job, the two fractions add up to one
\n" ); document.write( "\"t%2F7\" + \"t%2F5\" = 1
\n" ); document.write( "multiply by the least common factor of 7 and 5, 35:
\n" ); document.write( "35*\"t%2F7\" + 35*\"t%2F5\" = 35
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "5t + 7t = 35
\n" ); document.write( "12t = 35
\n" ); document.write( "t = 35/12
\n" ); document.write( "t = 2\"11%2F12\" hrs which is 2 + \"11%2F12\"*60 = 2 hrs 55 min
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