document.write( "Question 989069: Baseballs from straight upward with an initial speed of 64 feet a second the number of feet S above the ground after T seconds is given by the equation s= -16 T squared +64t. when will the baseball be 48 feet above ?the ground when will he hit the ground? \n" ); document.write( "
Algebra.Com's Answer #609503 by Boreal(15235)\"\" \"About 
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h=-16t^2+64t
\n" ); document.write( "h=48
\n" ); document.write( "Therefore, -16t^2+64t=48,
\n" ); document.write( "16t^2-64t+48=0
\n" ); document.write( "dividing by 16
\n" ); document.write( "t^2-4t+3=0
\n" ); document.write( "(t-3)(t-1)=0
\n" ); document.write( "and t=1 and 3 seconds it will be 48 feet above the ground.
\n" ); document.write( "It will hit the ground when -16t^2+64t=0, or t=4 seconds.
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C5%2C-5%2C75%2C-16x%5E2%2B64x%29\"
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