document.write( "Question 988980: A piece of sheet metal, w = 24 inches wide, is bent to form the gutter shown in the illustration. If the cross-sectional area is 54 square inches, find the depth of the gutter. (Enter your answers as a comma-separated list.) \r
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Algebra.Com's Answer #609477 by macston(5194)\"\" \"About 
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\n" ); document.write( "W=width; H=height
\n" ); document.write( ".
\n" ); document.write( "W+2H=24in
\n" ); document.write( "W=24in-2H
\n" ); document.write( ".
\n" ); document.write( "Area=WH
\n" ); document.write( "54in^2=WH
\n" ); document.write( "54in^2=(24-2H)(H)
\n" ); document.write( "54in^2=24H-2H^2
\n" ); document.write( "2H^2-24H+54=0
\n" ); document.write( "H^2-12H+27=0
\n" ); document.write( "(H-3)(H-9)=0
\n" ); document.write( "H-3=0 OR H-9=0
\n" ); document.write( "H=3 OR H=9
\n" ); document.write( "W=24-2H
\n" ); document.write( "W=24-2(3) OR W=24-2(9)
\n" ); document.write( "W=24-6 or W=24-18
\n" ); document.write( "W=18 or W=6
\n" ); document.write( "If width=18, height=3; if width=6, height=9
\n" ); document.write( ".
\n" ); document.write( "The picture can not match the problem. The 24 inch wide metal cannot be formed to have a width=2x and height=x AND have a cross sectional area of 54 in^2\r
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