document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988994>Question 988994</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy is 12 years old. His mother is four times as old as he is.  In x years time the mother will be three times as old as the son. Form an equation in x and hence find x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609455 by </B><A HREF=/tutors/aboutme.mpl?userid=jhunjiro><B>jhunjiro(67)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jhunjiro><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jhunjiro><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "age of boy = 12<BR>\n" );
document.write( "age of mother = 4 times age of boy = 4*12 = 48\r<BR>\n" );
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document.write( "let x = years time\r<BR>\n" );
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document.write( "3(12+x) = 48+x<BR>\n" );
document.write( "36+3x = 48+x<BR>\n" );
document.write( "3x-x = 48-36<BR>\n" );
document.write( "2x = 12<BR>\n" );
document.write( "x = 6\r<BR>\n" );
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document.write( "In 6 years time the mother will be three times as old as the son.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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