document.write( "Question 988742: Andrew invests $8000 in two types of accounts: a savings account that pays 5.25% interest per year and a more risky account that pays 9% interest per year. At the end of the year he has $450 in interest from the two accounts. Find the amount of money invested in each account \n" ); document.write( "
Algebra.Com's Answer #609417 by macston(5194)\"\" \"About 
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\n" ); document.write( "F=amount at 5.25%; N=amount at 9%
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\n" ); document.write( "F+N=$8000
\n" ); document.write( "N=$8000-F
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\n" ); document.write( "0.0525F+0.09N=$450
\n" ); document.write( "0.0525F+0.09($8000-F)=$450
\n" ); document.write( "0.0525F+$720-0.09F=$450
\n" ); document.write( "-0.0375F=-$270
\n" ); document.write( "F=$7200 ANSWER 1: $7200 was invested at 5.25%.
\n" ); document.write( "N=$8000-$7200=$800 ANSWER 2: $800 was invested at 9%.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.0525F+0.09N=$450
\n" ); document.write( "0.0525($7200)+0.09($800)=$450
\n" ); document.write( "$378+$72=$450
\n" ); document.write( "$450=$450\r
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