document.write( "Question 988842: Russell invests $8100 in two different accounts. The first account paid 4 %, the second account paid 10 % in interest. At the end of the first year he had earned $504 in interest. How much was in each account?\r
\n" ); document.write( "\n" ); document.write( "$  at 4 %\r
\n" ); document.write( "\n" ); document.write( "$  at 10 %
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Algebra.Com's Answer #609403 by macston(5194)\"\" \"About 
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\n" ); document.write( "F=amount at 4%; T=amount at 10%
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\n" ); document.write( "F+T=$8100
\n" ); document.write( "T=$8100-F
\n" ); document.write( ".
\n" ); document.write( "0.04F+0.10T=$504
\n" ); document.write( "0.04F+0.10($8100-F)=$504
\n" ); document.write( "0.04F+$810-0.10F=$504
\n" ); document.write( "-0.06F=-$306
\n" ); document.write( "F=$5100 ANSWER 1: $5100 was in the 4% account.
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\n" ); document.write( "T=$8100-F=$8100-$5100=$3000 ANSWER 2: $3000 was in the 10% account.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.04F+0.10T=$504
\n" ); document.write( "0.04($5100)+0.10($3000)=$504
\n" ); document.write( "$204+$300=$504
\n" ); document.write( "$504=$504
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