document.write( "Question 988842: Russell invests $8100 in two different accounts. The first account paid 4 %, the second account paid 10 % in interest. At the end of the first year he had earned $504 in interest. How much was in each account?\r
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document.write( "$ at 4 %\r
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document.write( "$ at 10 % \n" );
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Algebra.Com's Answer #609403 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "F=amount at 4%; T=amount at 10% \n" ); document.write( ". \n" ); document.write( "F+T=$8100 \n" ); document.write( "T=$8100-F \n" ); document.write( ". \n" ); document.write( "0.04F+0.10T=$504 \n" ); document.write( "0.04F+0.10($8100-F)=$504 \n" ); document.write( "0.04F+$810-0.10F=$504 \n" ); document.write( "-0.06F=-$306 \n" ); document.write( "F=$5100 ANSWER 1: $5100 was in the 4% account. \n" ); document.write( ". \n" ); document.write( "T=$8100-F=$8100-$5100=$3000 ANSWER 2: $3000 was in the 10% account. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "0.04F+0.10T=$504 \n" ); document.write( "0.04($5100)+0.10($3000)=$504 \n" ); document.write( "$204+$300=$504 \n" ); document.write( "$504=$504 \n" ); document.write( " \n" ); document.write( " |