document.write( "Question 988875: -2^-3 - 3/-3^-2-3^0 I have no clue how to work? \n" ); document.write( "
Algebra.Com's Answer #609349 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"%28%28-2%29%5E%28-3%29+-+3%29%2F%28%28-3%29%5E%28-2%29-3%5E0+%29\"\r
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\n" ); document.write( "\n" ); document.write( "recall the rules: \"a%5E%28-m%29=1%2Fa%5Em\" and \"a%5E0=1\"\r
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\n" ); document.write( "\n" ); document.write( "so, you have:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28-2%29%5E%28-3%29+-+3%29%2F%28%28-3%29%5E%28-2%29-3%5E0+%29\"....apply rules\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F%28-2%29%5E3+-+3%29%2F%281%2F%28-3%29%5E2-1+%29\".....\"%28-2%29%5E3=%28-2%29%28-2%29%28-2%29=-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F%28-8%29+-+%283%2A8%29%2F8%29%2F%281%2F9-1+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-1%2F8+-+24%2F8%29%2F%281%2F9-9%2F9+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-25%2F8%29%2F%28-8%2F9+%29\"...........use the rule \"%28a%2Fb%29%2F%28c%2Fd%29=ad%2Fbc\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-25%2A9%29%2F%288%28-8%29+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-225%29%2F%28-64%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3.515625\".........round it to two decimal places\r
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\n" ); document.write( "\n" ); document.write( "\"3.52\"\r
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