document.write( "Question 988848: Determine the equation of the straight line through the points (-2;1) and (3;-2) \n" ); document.write( "
Algebra.Com's Answer #609329 by Shai(25)\"\" \"About 
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Given A(-2,1) B(3,-2)
\n" ); document.write( "Slope=(y2-y1)/(x2-x1)
\n" ); document.write( "Slope=(-2-1)/((3-(-2))
\n" ); document.write( "Let us represent the slope here as m
\n" ); document.write( "Thus the equation of the line is
\n" ); document.write( "m(x-x1)=(y-y1)
\n" ); document.write( "Henceforth,
\n" ); document.write( "(-3/5)(x+2)=(y-1)
\n" ); document.write( "Thus the equation of the line is
\n" ); document.write( "3x+5y+1=0
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