document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988841>Question 988841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Emma invests $900 in one account and $1800 in an account paying 3 % higher interest. At the end of one year she had earned $135 in interest. At what rates did she invest?\r<BR>\n" );
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document.write( "$900 invested at %\r<BR>\n" );
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document.write( "$1800 invested at % </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609318 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Emma invests $900 in one account and $1800 in an account paying 3 % higher interest. At the end of one year she had earned $135 in interest. At what rates did she invest?<BR>\n" );
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document.write( "(x/100)(900) + [(x+3)/100]1800 = 135<BR>\n" );
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document.write( "9x + 18x + 54 = 135<BR>\n" );
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document.write( "27x = 81<BR>\n" );
document.write( "x = 3<BR>\n" );
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document.write( "$900 invested at 3% <BR>\n" );
document.write( "$1800 invested at 6%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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