Algebra.Com's Answer #609269 by MathTherapy(10552)  You can put this solution on YOUR website! \n" );
document.write( "Solve for x in the inequality: \n" );
document.write( "-1 is less than (x+2)/(x-3)\r \n" );
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document.write( "Any tips, tricks, advice for other inequality problems is greatly appreciated as well as help with this problem! Thank you in advance! \n" );
document.write( " , with as this would make the denominator 0, and therefore, an UNDEFINED inequality \n" );
document.write( " ----- Multiplying both sides by LCD, x - 3 \n" );
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document.write( " -------- Subtracting 3 from both sides \n" );
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document.write( " --------- Subtracting x from both sides \n" );
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document.write( " -------- Inequality sign changes when dividing by a negative value \n" );
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document.write( "Now, we have the CRITICAL VALUES: \n" );
document.write( "This means that we will have THREE (3) TEST-INTERVALS to determine whether or not values \n" );
document.write( "in the intervals SATISFY the ORIGINAL inequality: . These TEST INTERVALS are: \n" );
document.write( "1)  \n" );
document.write( "2) , and \n" );
document.write( "3) \r \n" );
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document.write( "Testing with test value: , becomes:  \n" );
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document.write( "As the above is TRUE, the test-interval: IS a solution\r \n" );
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document.write( "Testing with test value: , becomes:  \n" );
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document.write( "As the above is FALSE, the test-interval: IS NOT a solution\r \n" );
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document.write( "Testing with test value: , becomes:  \n" );
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document.write( "As the above is TRUE, the test-interval: IS a solution \n" );
document.write( "In interval notation, this is: (- oo, ½) ᑌ (3, oo) , or (  ) ᑌ (  ) \n" );
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