document.write( "Question 988780: Use the definition of limit to verify that: \r
\n" ); document.write( "\n" ); document.write( "(1). lim x->3 (5-2x) = - 1\r
\n" ); document.write( "\n" ); document.write( "2). lim x->0 (4x+7) = 7 \r
\n" ); document.write( "\n" ); document.write( "(3). lim x->7 (2x)/(x^2+1) = 1 \r
\n" ); document.write( "\n" ); document.write( "Please explain how you solved.\r
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Algebra.Com's Answer #609258 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\,0\,\exists\,\delta\,\in\,\mathbb{R}\,>\,0\,:\,0\,<\,|x\ -\ a|\,<\,\delta\,\Rightarrow\,|f(x)\ -\ L|\,<\,\epsilon\">\r
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\n" ); document.write( "\n" ); document.write( "\,0\,\exists\,\delta\,\in\,\mathbb{R}\,>\,0\,:\,0\,<\,|x\ -\ 3|\,<\,\delta\,\Rightarrow\,|5\ -\ 2x\ -\ (-1)|\,<\,\epsilon\">\r
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\n" ); document.write( "\n" ); document.write( "\ x\ -\ 3\ >\ -\frac{\epsilon}{2}\">\r
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\n" ); document.write( "\n" ); document.write( "Choose . Then whenever \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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