document.write( "Question 988607: The fourth term of a geometric progression exceeds the third term by 54, and the sum of the second and third term is 36. Find the common ratio if it is positive \n" ); document.write( "
Algebra.Com's Answer #609192 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
The fourth term of a geometric progression exceeds the third term by 54, and the sum of the second and third term is 36. Find the common ratio if it is positive
\n" ); document.write( "
Since \"a%5B1%5D+=+a%5B1%5D\", then \"a%5B2%5D+=+a%5B1%5Dr\", \"a%5B3%5D+=+a%5B1%5Dr%5E2\", and \"a%5B4%5D+=+a%5B1%5Dr%5E3\"\r
\n" ); document.write( "\n" ); document.write( "Since \"a%5B4%5D\" exceeds \"a%5B3%5D\" by 54, then we can say that: \"a%5B1%5Dr%5E3+-+a%5B1%5Dr%5E2+=+54\"
\n" ); document.write( "\"a%5B1%5D%28r%5E3+-+r%5E2%29+=+54\"
\n" ); document.write( "\"a%5B1%5D+=+54%2F%28r%5E3+-+r%5E2%29\" ---------- eq (i)\r
\n" ); document.write( "\n" ); document.write( "Since the sum of \"a%5B2%5D\" and \"a%5B3%5D\" is 36, then we can say that: \"a%5B1%5Dr+%2B+a%5B1%5Dr%5E2+=+36\"
\n" ); document.write( "\"a%5B1%5D%28r+%2B+r%5E2%29+=+36\"
\n" ); document.write( "\"a%5B1%5D+=+36%2F%28r+%2B+r%5E2%29\" --------- eq (ii)\r
\n" ); document.write( "\n" ); document.write( "Since \"a%5B1%5D+=+54%2F%28r%5E3+-+r%5E2%29\" and \"a%5B1%5D+=+36%2F%28r+%2B+r%5E2%29\", we can then say that: \"54%2F%28r%5E3+-+r%5E2%29+=+36%2F%28r+%2B+r%5E2%29\"
\n" ); document.write( "\"54%28r+%2B+r%5E2%29+=+36%28r%5E3+-+r%5E2%29\" ------ Cross-multiplying
\n" ); document.write( "\"3%28r+%2B+r%5E2%29+=+2%28r%5E3+-+r%5E2%29\" -------- Factoring out GCF, 18
\n" ); document.write( "\"3r+%2B+3r%5E2+=+2r%5E3+-+2r%5E2\"
\n" ); document.write( "\"2r%5E3+-+2r%5E2+-+3r%5E2+-+3r+=+0\"
\n" ); document.write( "\"2r%5E3+-+5r%5E2+-+3r+=+0\"
\n" ); document.write( "\"r%282r%5E2+-+5r+-+3%29+=+r%280%29\"
\n" ); document.write( "\"2r%5E2+-+5r+-+3+=+0\"
\n" ); document.write( "(r - 3)(2r + 1) = 0
\n" ); document.write( "Common ratio, or \"highlight_green%28r+=+3%29\" OR \"r+=+-+1%2F2\" (ignore, since r MUST be > 0) \n" ); document.write( "
\n" );