document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988705>Question 988705</A>: <I><SPAN STYLE=\"word-break: break-all;\">  When a polynomial is divided by (x-5).  The quotient Is 5x^2+3x+12 with a  remainder  7.  Find the polynomial. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609186 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you multiply the two factors, you get 5x^3-22x^2-3x-60.  The polynomial needs a -53 so that when synthetic division is done using 5, the last term is  -53+(12*5)=7<BR>\n" );
document.write( "The polynomial is 5x^3-22x^2-3x-53<BR>\n" );
document.write( "5/5 ;;-22;;-3;;-53<BR>\n" );
document.write( ";;;5;; 3;;12; 7<BR>\n" );
document.write( " </SPAN>\n" );
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