document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988685>Question 988685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 10 meters, the area of the rectangle that is formed is 75 square meters. Find the area of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609181 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Original Square, x by x<BR>\n" );
document.write( "Area x^2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "New Square, x+12  by  x-10<BR>\n" );
document.write( "Area (x+12)(x-10)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B12%29%28x-10%29=75 ALIGN=MIDDLE  ALT=\"%28x%2B12%29%28x-10%29=75\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Solve for x. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );