document.write( "Question 988671: Find the dimensions of a rectangle whose area is 187 cm2 and whose perimeter is 56 cm. (Enter your answers as a comma-separated list.) \n" ); document.write( "
Algebra.Com's Answer #609169 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The sum of the length and the width of a rectangle is half of the perimeter. Proof of this assertion is left as an exercise for the student.\r
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\n" ); document.write( "\n" ); document.write( "For this rectangle, length plus width equals 28, so we can say .\r
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\n" ); document.write( "\n" ); document.write( "Then we know that the area, which is the product of the length times the width, is 187. Substituting from above:\r
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\n" ); document.write( "\n" ); document.write( "Solve the quadratic. One of the roots is the width, the other is the length.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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