document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988671>Question 988671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose area is 187 cm2 and whose perimeter is 56 cm. (Enter your answers as a comma-separated list.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609166 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=56;L+W=28<BR>\n" );
document.write( "LW=187<BR>\n" );
document.write( "L=187/W<BR>\n" );
document.write( "187/W+W=28<BR>\n" );
document.write( "187+W^2=28W, multiplying by W<BR>\n" );
document.write( "W^2-28W+187=0<BR>\n" );
document.write( "W=(1/2)(28+/-) sqrt (784-748);sqrt term =6<BR>\n" );
document.write( "W=17 or 11<BR>\n" );
document.write( "L=11 or 17<BR>\n" );
document.write( "By convention, L is longer, so it is 17*11<BR>\n" );
document.write( "17,11,17,11 is perimeter<BR>\n" );
document.write( "17*11 is area.  <BR>\n" );
document.write( "Notice that the roots are interchangeable.\r<BR>\n" );
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