document.write( "Question 988659: Granville and preston are 642 miles apart. A car leaves preston bound for granville at 50mph. At the same time, another car leaves Granville bound for preston at 57mph. How long will it take them to meet? \n" ); document.write( "

Algebra.Com's Answer #609152 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The easiest way to solve this is to
\n" ); document.write( "think of one car as standing still and
\n" ); document.write( "the other traveling at the sum of their speeds
\n" ); document.write( "( it doesn't matter which one is standing still )
\n" ); document.write( "----------------
\n" ); document.write( "Let $\"+t+\"$ = time in hrs for them to meet
\n" ); document.write( " $\"+642+=%28+50+%2B+57+%29%2At+\"$
\n" ); document.write( " $\"+642+=+107t+\"$
\n" ); document.write( " $\"+t+=+6+\"$
\n" ); document.write( "It takes 6 hrs for them to meet
\n" ); document.write( "----------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+d%5B1%5D+=+50t+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+50%2A6+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+300+\"$ mi
\n" ); document.write( "and
\n" ); document.write( " $\"+d%5B2%5D+=+57t+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+57%2A6+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+342+\"$ mi
\n" ); document.write( "------------------
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+300+%2B+342+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+642+\"$ mi
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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