document.write( "Question 988657: Find the area enclosed by the curve x=t^2 - 2t, y=sqrt(t) and the y-axis. \n" ); document.write( "
Algebra.Com's Answer #609149 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Find the area enclosed by the curve x=t^2 - 2t, y=sqrt(t) and the y-axis.
\n" ); document.write( "------------
\n" ); document.write( "Eliminate t
\n" ); document.write( "----
\n" ); document.write( "x=t^2 - 2t
\n" ); document.write( "y=sqrt(t) --> t = y^2
\n" ); document.write( "x = y^4 - 2y^2
\n" ); document.write( "===============
\n" ); document.write( "The area is the same as y = x^4 - 2x^2 and the x-axis
\n" ); document.write( "-----
\n" ); document.write( "Find the 2 x-intercepts:
\n" ); document.write( "x = 0 is one.
\n" ); document.write( "\"x%5E2+-+2+=+0\"
\n" ); document.write( "--> \"x+=+sqrt%282%29\"
\n" ); document.write( "=================-
\n" ); document.write( "INT(x^4 - 2x^2) = x^5/5 - 2x^3/3
\n" ); document.write( "Area = |\"%28sqrt%282%29%29%5E5%2F5+-+2%28sqrt%282%29%29%5E3%2F3\"|
\n" ); document.write( "=~ 0.754247 sq units
\n" ); document.write( "
\n" );