document.write( "Question 988589: HI, this question is from my textbook.
\n" ); document.write( "The equations of two sides of a square are y=3x-1 and x+3y-6=0. (0,-1) is one vertex of the square. Find the coordinates of the other vertices.
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Algebra.Com's Answer #609141 by KMST(5328)\"\" \"About 
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\"y=3x-1\" , and \"x%2B3y-6=0\" are the equations of two sides of the square.
\n" ); document.write( "The coordinates of the vertex at the intersection of those two sides can be found by solving the system
\n" ); document.write( "\"system%28y=3x-1%2Cx%2B3y-6=0%29\"--->\"system%28y=3x-1%2Cx%2B3%283x-1%29-6=0%29\"--->\"system%28y=3x-1%2Cx%2B9x-3-6=0%29\"--->\"system%28y=3x-1%2C10x-9=0%29\"--->\"system%28y=3x-1%2Cx=9%2F10%29\"--->\"system%28y=3%289%2F10%29-1%2Cx=9%2F10%29\"--->\"system%28y=27%2F10%29-10%2F10%2Cx=9%2F10%29\"--->\"highlight%28system%28y=17%2F10%2Cx=9%2F10%29%29\" .
\n" ); document.write( "So, point (9/10,17/10), or (0.9,1.7) is one vertex,
\n" ); document.write( "the one at the intersection of the two given sides.
\n" ); document.write( "Point (0,-1) , with \"system%28x=0%2Cy=-1%29\" is the other end/vertex of that side with equation \"y=3x-1\" .
\n" ); document.write( "So far we have this:
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\n" ); document.write( "What we do not know is to what side of segment \"red%28AB%29\" to draw the square.
\n" ); document.write( "There are really two right answers. Which one will be the right one according to your textbook? Or did the authors realize that there were two possible answers?
\n" ); document.write( "We can draw the square to the right, like this:
\n" ); document.write( " , or we can draw the square to the left, as Alan suggested.
\n" ); document.write( "Either way, if we encase that square inside a larger square with sides parallel to the x- and y-axes,
\n" ); document.write( "we form four congruent right triangles with legs measuring
\n" ); document.write( "\"x%5BB%5D-x%5BA%5D=0.9-0=0.9\" and \"y%5BB%5D-y%5BA%5D=1.7-%28-1%29=2.7\" , like this
\n" ); document.write( "So, \"x%5BE%5D=x%5BB%5D%2B2.7=0.9%2B2.7=3.6\" , \"y%5BE%5D=y%5BB%5D-0.9=1.7-0.9=0.8\" ,
\n" ); document.write( "\"x%5BF%5D=x%5BA%5D%2B2.7=0%2B2.7=2.7\" , and \"y%5BF%5D=y%5BA%5D-0.9=-1-0.9=-1.9\" .
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