document.write( "Question 988589: HI, this question is from my textbook.
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document.write( "The equations of two sides of a square are y=3x-1 and x+3y-6=0. (0,-1) is one vertex of the square. Find the coordinates of the other vertices. \n" );
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Algebra.Com's Answer #609123 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The equations of two sides of a square are y=3x-1 and x+3y-6=0. (0,-1) is one vertex of the square. Find the coordinates of the other vertices. \n" ); document.write( "--------------- \n" ); document.write( "(0,-1) is point A. \n" ); document.write( "Find the intersection of the lines, that's a 2nd vertex, point B. \n" ); document.write( "--- \n" ); document.write( "y=3x-1 \n" ); document.write( "x+3y-6=0 --> y = (-1/3)x + 2 \n" ); document.write( "----------- \n" ); document.write( "x + 3(3x-1) = 6 \n" ); document.write( "10x = 9 \n" ); document.write( "x = 0.9, y = 1.7 --> B(0.9,1.7) \n" ); document.write( "----------- \n" ); document.write( "The distance between the 2 points is the side length. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------- \n" ); document.write( "Find the line thru A(0,-1) parallel to x+3y-6=0 \n" ); document.write( "--> y = (-1/3)x - 1 \n" ); document.write( "A vertex (point D) is on this line distance s from point A. \n" ); document.write( "The x-distance from A to D is 2.7, and the y-distance is 0.9 \n" ); document.write( "--> D (-2.7,-0.1) \n" ); document.write( "------------------ \n" ); document.write( "The side CD goes thru D with a slope of 3 (parallel to AB) \n" ); document.write( "y + 0.1 = 3(x + 2.7) \n" ); document.write( "y = 3x + 8 \n" ); document.write( "--- \n" ); document.write( "Vertex C is the intersection of y = 3x + 8 and y = (-1/3)x + 2 \n" ); document.write( "3x + 8 = -x/3 + 2 \n" ); document.write( "10x/3 = -6 \n" ); document.write( "x = -1.8, y = 2.6 \n" ); document.write( "C(-1.8,2.6) \n" ); document.write( " \n" ); document.write( " |