document.write( "Question 988618: A man spends money according to the date.
\n" ); document.write( "Eg: On 15th he will spend 15rs, 19th he will spend 19rs.
\n" ); document.write( "One night he will count 5 consecutive days and the amount equals to 61. \r
\n" ); document.write( "\n" ); document.write( "What are those 5 consecutive dates? \n" ); document.write( "

Algebra.Com's Answer #609116 by KMST(5328) $\"\"$ $\"About$

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The five consecutive dates are:
\n" ); document.write( "February 27, February 28, March 1, March 2, and March 3 of a year that is not a leap year.
\n" ); document.write( "Five consecutive days often will be in the same month and hence consecutively numbered, as in
\n" ); document.write( " $\"n-2\"$ , $\"n-1\"$ , $\"n\"$ , $\"n%2B1\"$ , and $\"n%2B2\"$ , which add up to
\n" ); document.write( " $\"n-2%2Bn-1%2Bn%2Bn%2B1%2Bn%2B2=5n\"$ , so the sum would be a multiple of 5.
\n" ); document.write( "Since $\"61\"$ is not a multiple of 5,
\n" ); document.write( "the 5 consecutive days must include the end of a month and the beginning of the next month.
\n" ); document.write( "If the first month $\"30\"$ or $\"31\"$ days,
\n" ); document.write( "the possible sums do not add up to $\"61\"$ :
\n" ); document.write( " $\"30%2B31%2B1%2B2%2B3=67\"$ , $\"31%2B1%2B2%2B3%2B4=41\"$ ,
\n" ); document.write( " $\"29%2B30%2B1%2B2%2B3=65\"$ , $\"30%2B1%2B2%2B3%2B4=40\"$ .
\n" ); document.write( "So, the first month must be February, with $\"28\"$ or $\"29\"$ days.
\n" ); document.write( "Since $\"28%2B2=30\"$ and $\"27%2B3=30\"$ ,
\n" ); document.write( "the sum $\"27%2B28%2B1%2B2%2B3=61\"$ works.
\n" ); document.write( "The other possibility with two days in February and three in March,
\n" ); document.write( " $\"29%2B28%2B1%2B2%2B3=63\"$ , yields a sum that is too high,
\n" ); document.write( "and using only one day from February will yield too low a sum. \n" ); document.write( "

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