document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988612>Question 988612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rick and Mike are roommates and leave Gainesville on Interstate 75 at the same time to visit their girlfriends for a long weekend. Rick travels north and Mike travels south. If Mike's average speed is 6 mph faster than Rick's, find the speed of each if they are 207 miles apart in 1 hour and 30 minutes. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609111 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of their speeds is:<BR>\n" );
document.write( "207mi/1.5hr=138 mph <BR>\n" );
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document.write( "M=Mike's speed; R=rick's speed=M-6mph<BR>\n" );
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document.write( "M+R=138 mph<BR>\n" );
document.write( "M+M-6mph=138 mph<BR>\n" );
document.write( "2M=144 mph<BR>\n" );
document.write( "M=72 mph<BR>\n" );
document.write( "ANSWER 1: Mike's speed was 72 mph.<BR>\n" );
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document.write( "R=M-6mph=72mph-6mph=66mph<BR>\n" );
document.write( "ANSWER 2: Rick's speed was 66 mph.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
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document.write( "1.5(M)+1.5(R)=207 mi<BR>\n" );
document.write( "1.5hr(72mph)+1.5hr(66mph)=207mi<BR>\n" );
document.write( "108mi+99mi=207mi<BR>\n" );
document.write( "207mi=207mi<BR>\n" );
document.write( " </SPAN>\n" );
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