document.write( "Question 988583: a number is five less than three times another number. The sum of the two numbers is 55. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #609104 by macston(5194)\"\" \"About 
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\n" ); document.write( "x and y are the two numbers
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\n" ); document.write( "x+y=55
\n" ); document.write( "x=55-y Use this to substitute for x.
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\n" ); document.write( "x=3y-5 Substitute for x.
\n" ); document.write( "55-y=3y-5
\n" ); document.write( "60=4y
\n" ); document.write( "15=y ANSWER 1: One of the numbers is 15.
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\n" ); document.write( "x=55-y=55-15=40 ANSWER 2: the other number is 40.
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\n" ); document.write( "CHECK:
\n" ); document.write( "x=3y-5
\n" ); document.write( "40=3(15)-5
\n" ); document.write( "40=45-5
\n" ); document.write( "40=40
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