document.write( "Question 988590: A 20% dye solution is to be mixed with a 90% dye solution to get 140 liters of a 50% solution. How many liters of the 20% and 90% solutions will be needed? \n" ); document.write( "
Algebra.Com's Answer #609103 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "x=amount of 20% solution; y=amount of 90% solution=140L-x \n" ); document.write( ". \n" ); document.write( "0.20x+0.90y=0.50(140L) \n" ); document.write( "0.20x+0.90(140L-x)=0.50(140L) \n" ); document.write( "0.20x+126L-0.90x=70L \n" ); document.write( "-0.70x=-56L \n" ); document.write( "x=80L \n" ); document.write( "ANSWER 1: 80 liters of 20% solution will be needed. \n" ); document.write( ". \n" ); document.write( "y=140L-x=140L-80L=60L \n" ); document.write( "ANSWER 2: 60 liters of 90% solution will be needed. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "0.20x+0.90y=0.50(140L) \n" ); document.write( "0.20(80L)+0.90(60L)=0.50(140L) \n" ); document.write( "16L+54L=70L \n" ); document.write( "70L=70L \n" ); document.write( " |