document.write( "Question 988454: The perimeter of a rectangle is 36 and the length is twice the width. What are the dimensions of this rectangle? \n" ); document.write( "
Algebra.Com's Answer #609061 by macston(5194)![]() ![]() You can put this solution on YOUR website! W=width; L=length=2W \n" ); document.write( ". \n" ); document.write( "P=2(L+W) \n" ); document.write( "36=2(L+W) \n" ); document.write( "18=L+W Substitute for L. \n" ); document.write( "18=2W+W \n" ); document.write( "18=3W \n" ); document.write( "6=W ANSWER 1: Width is 6 units. \n" ); document.write( "L=2W+2(6)=12 ANSWER 2: Length is 12 units \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "P=2(L+W) \n" ); document.write( "36=2(12+6) \n" ); document.write( "36=2(18) \n" ); document.write( "36=36 \n" ); document.write( " |