document.write( "Question 988454: The perimeter of a rectangle is 36 and the length is twice the width. What are the dimensions of this rectangle? \n" ); document.write( "
Algebra.Com's Answer #609061 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
W=width; L=length=2W
\n" ); document.write( ".
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "36=2(L+W)
\n" ); document.write( "18=L+W Substitute for L.
\n" ); document.write( "18=2W+W
\n" ); document.write( "18=3W
\n" ); document.write( "6=W ANSWER 1: Width is 6 units.
\n" ); document.write( "L=2W+2(6)=12 ANSWER 2: Length is 12 units
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "36=2(12+6)
\n" ); document.write( "36=2(18)
\n" ); document.write( "36=36
\n" ); document.write( "
\n" );