document.write( "Question 988537: You invested a total of 40,000 at 3% and 4 1/2% simple interest. During one year, the two accounts earned $1575. How much did you invest in each account \n" ); document.write( "
Algebra.Com's Answer #609049 by macston(5194)\"\" \"About 
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\n" ); document.write( "T=amount at 3%; F=amount at 4.5%
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\n" ); document.write( "T+F=$40000
\n" ); document.write( "T=40000-F Use to substitute for T.
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\n" ); document.write( "0.03T+0.045F=$1575 Substitute for T.
\n" ); document.write( "0.03($40000-F)+0.045F=$1575
\n" ); document.write( "$1200-0.03F+0.045F=$1575
\n" ); document.write( "0.015F=$375
\n" ); document.write( "F=$25000 ANSWER 1: $25000 was invested at 4.5%.
\n" ); document.write( "T=$40000-F=$40000-$25000=%15000 ANSWER 2: $15000 was invested at 3%.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "0.03T+0.045F=$1575
\n" ); document.write( "0.03($15000)+0.045($25000)=$1575
\n" ); document.write( "$450+$1125=$1575
\n" ); document.write( "$1575=$1575\r
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