document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988532>Question 988532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $5000 was invested, part of it at 4% per year and the remainder at 6% per year. If the total yearly interest amounted to $270, how much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #609047 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=609047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A total of $5000 was invested, part of it at 4% per year and the remainder at 6% per year. If the total yearly interest amounted to $270, how much was invested at each rate? \r<BR>\n" );
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document.write( "let x=amt invested at 4%<BR>\n" );
document.write( "5000-x=amt invested at 6%\r<BR>\n" );
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document.write( ".04x+.06(5000-x)=270<BR>\n" );
document.write( ".04x+300-.06x=270<BR>\n" );
document.write( ".02x=30<BR>\n" );
document.write( "x=1500<BR>\n" );
document.write( "5000-x=3500<BR>\n" );
document.write( "amt invested $1500<BR>\n" );
document.write( "5000-x=amt invested at 6%=$3500\r<BR>\n" );
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document.write( " </SPAN>\n" );
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