document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84561>Question 84561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by addition or substitution.<BR>\n" );
document.write( "	3x + 6y = 0<BR>\n" );
document.write( "              x = 2/3 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60900 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=2/3<BR>\n" );
document.write( "3*2/3+6Y=0<BR>\n" );
document.write( "6/3+6Y=0<BR>\n" );
document.write( "2+6Y=0<BR>\n" );
document.write( "6Y=-2<BR>\n" );
document.write( "Y=-2/6<BR>\n" );
document.write( "Y=-1/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );