document.write( "Question 988251: A circular magnet has an inner radius of r-cm, an outer radius 2cm larger and its depth is the same as the inner radius. If the total volume of the magnet is 120 mulitplied by pi cm^3, find r.
\n" ); document.write( "I have written the equation, but cannot solve it.
\n" ); document.write( "V= pi x (r+2)^2 x r - pi x r^2 x r
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Algebra.Com's Answer #608989 by ankor@dixie-net.com(22740)\"\" \"About 
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A circular magnet has an inner radius of r-cm, an outer radius 2cm larger and its depth is the same as the inner radius. If the total volume of the magnet is 120 mulitplied by pi cm^3, find r.
\n" ); document.write( "I have written the equation, but cannot solve it.
\n" ); document.write( "V= pi x (r+2)^2 x r - pi x r^2 x r
\n" ); document.write( "just make equal to 120pi
\n" ); document.write( "\"%28pi%2A%28r%2B2%29%5E2%2Ar%29+-+%28pi%2Ar%5E2%2Ar%29+=+120%2Api\"
\n" ); document.write( "divide thru by pi, multiply r
\n" ); document.write( "\"%28r%28r%2B2%29%5E2%29+-+r%5E3+=+120\"
\n" ); document.write( "FOIL (r+2)(r+2)
\n" ); document.write( "\"r%28r%5E2+%2B+4r+%2B+4%29+-+r%5E3+=+120\"
\n" ); document.write( "\"r%5E3%2B+4r%5E2+%2B+4r+-+r%5E3+=+120\"
\n" ); document.write( "r^3 cancel so we have
\n" ); document.write( "\"4r%5E2+%2B+4r+=+120\"
\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "\"r%5E2+%2B+r+=+30\"
\n" ); document.write( "A quadratic equation
\n" ); document.write( "\"r%5E2+%2B+r+-+30+=+0\"
\n" ); document.write( "factors to
\n" ); document.write( "(r+6)(r-5) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "r = 5
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you?
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