document.write( "Question 988419: You pick two cards from a standard deck of 52 cards. What is the probability you choose a 9 and then an ace if you do not replace the first card.\r
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Algebra.Com's Answer #608981 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The probability of anything is the number of ways the event can happen that you would consider a success divided by the number of ways that it can happen at all. To get the 9, of which there are 4 in the deck of 52, you have a 4/52 or 1/13 chance. Then, since you didn't replace the first card, you want, on the second draw, to select one of four aces out of what is now 51 cards.\r
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\n" ); document.write( "\n" ); document.write( "Since you calculated the second probability based on the assumption that the first draw was successful, the two draws become independent events. Hence, the overall probability is the product of the two probabilities.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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